document.write( "Question 1070264: Laura is bowling five games, her scores from the first 4 games are,133,112,94, and 108, for an average of least 125.2,what score in the 5th game is needed \n" ); document.write( "
Algebra.Com's Answer #685389 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! To find the average, add the scores and divide by the number of scores.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = the needed score\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "133 + 112 + 94 + 108 + x \n" ); document.write( "------------------------- = 125.2 {added the scores and divided by the number of scores} \n" ); document.write( " 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "447 + x \n" ); document.write( "-------- = 125.2 {added in numerator} \n" ); document.write( "5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "447 + x = 626 {multiplied each side by 5}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 179 {subtracted 447 from each side}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "179 is the needed score \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |