document.write( "Question 1070251: Airplane 1 leaves city A for city B at the same time Airplane 2 leaves city B for city A. The distance from city A to city B is 565 miles. If Airplane 1 travels at 560 miles per hour and Airplane 2 travels at 570 miles per​ hour, how long into their flights will the two planes pass each​ other?\r
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Algebra.Com's Answer #685378 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "Airplane 1 leaves city A for city B at the same time Airplane 2 leaves city B for city A. The distance from city A to city B is 565 miles.
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document.write( "t = \"565%2F%28560%2B570%29\" = \"565%2F1130\" = 0.5 of an hour = 30 minutes.   (*)\r\n" );
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document.write( "The numerator 565 is the distance, in miles;\r\n" );
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document.write( "the denominator 560 + 570 = 1130 is the relative speed of the two planes, or the rate of decreasing the distance between them.\r\n" );
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document.write( "The formula (*) which I used is the standard formula  t = \"distance%2FRate\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "On such problems, see the introductory lesson\r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems \r
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\n" ); document.write( "\n" ); document.write( "There is a bunch of lessons on Travel and Distance in this site.\r
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\n" ); document.write( "\n" ); document.write( "See the online textbook \r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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