document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1070179>Question 1070179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cook needs to mix a regular ranch dressing containing 47&#8203;% fat with a light ranch dressing containing 37&#8203;% fat to result in 7 cups of a dressing containing 42&#8203;% fat. How many cups of each kind of dressing should be&#8203; mixed?<BR>\n" );
document.write( "The mixture should contain <BR>\n" );
document.write( "how many cups of regular dressing and <BR>\n" );
document.write( "how many cups of light dressing?\r<BR>\n" );
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document.write( "Thank you SO much for the help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #685300 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=685300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 42% is half way between the two percentages, so use 3.5 cups of each.<BR>\n" );
document.write( "one can say x cups of 47%<BR>\n" );
document.write( "7-x cups of 37%<BR>\n" );
document.write( ".47(x)+(7-x)(.37)=7(.42)=2.94<BR>\n" );
document.write( ".47x+2.59-.37x=2.94<BR>\n" );
document.write( ".10x=0.35<BR>\n" );
document.write( "x=3.5 cups </SPAN>\n" );
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