document.write( "Question 262337: The points(-1,-7) and (5,10) are the endpoints of the diameter of a circle. Graph the circle. Find an equation of the circle.\n" ); document.write( " Cordinates of Midpoint of diameter of a circle=((x1 x2)/2, (y1 y2)/2): ((-1 5)/2, (-7 10)/2)=(2, 3/2). Where a=2 and b=3/2, radius r^2 =(a-x1)^2 (b-x2)^2: r^2=(2--1)^2 (3/2--7)^2, r=9.01. Eqn of circle: (x-a)^2 (y-b)^2=r^2: (x-2)^2 (y-3/2)^2=81.25. \n" ); document.write( "
Algebra.Com's Answer #685281 by cov20(1)![]() ![]() ![]() You can put this solution on YOUR website! The points(-1,-7) and (5,10) are the endpoints of the diameter of a circle. Graph the circle. Find an equation of the circle.\n" ); document.write( " Cordinates of Midpoint of diameter of a circle=((x1 x2)/2, (y1 y2)/2): ((-1 5)/2, (-7 10)/2)=(2, 3/2). Where a=2 and b=3/2, radius r^2 =(a-x1)^2 (b-x2)^2: r^2=(2--1)^2 (3/2--7)^2, r=9.01. Eqn of circle: (x-a)^2 (y-b)^2=r^2: (x-2)^2 (y-3/2)^2=81.25. \n" ); document.write( " |