document.write( "Question 1070095: The 12th 85th and last terms of an arithmetic progression are 38 257 and 395 respectively. Find the number of term.
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Algebra.Com's Answer #685246 by Fombitz(32388)\"\" \"About 
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\"a%5Bn%5D=a%5B1%5D%2B%28n-1%29d\"
\n" ); document.write( "\"a%5B12%5D=a%5B1%5D%2B%2812-1%29d=38\"
\n" ); document.write( "\"a%5B1%5D%2B11d=38\"
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\n" ); document.write( "\"a%5B1%5D%2B84d=257\"
\n" ); document.write( "Subtracting the first equation from this equation,
\n" ); document.write( "\"a%5B1%5D%2B84d-a%5B1%5D-11d=257-38\"
\n" ); document.write( "\"73d=219\"
\n" ); document.write( "\"d=3\"
\n" ); document.write( "Then,
\n" ); document.write( "\"a%5B1%5D%2B11%283%29=38\"
\n" ); document.write( "\"a%5B1%5D%2B33=38\"
\n" ); document.write( "\"a%5B1%5D=5\"
\n" ); document.write( "So then,
\n" ); document.write( "\"a%5B1%5D%2B%28k-1%29d=395\"
\n" ); document.write( "Find k.
\n" ); document.write( "\"5%2B%28k-1%293=395\"
\n" ); document.write( "\"%28k-1%293=390\"
\n" ); document.write( "\"k-1=130\"
\n" ); document.write( "\"k=131\"
\n" ); document.write( "131 terms
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