document.write( "Question 1070015: there is $4.50 in a bag of change, we have nickels, dimes and quarters, if we have a total of 28 coins, how many of each do I have??? \n" ); document.write( "
Algebra.Com's Answer #685170 by josgarithmetic(39801) ![]() You can put this solution on YOUR website! $4.50 could be made with 18 quarters, but you want 28 total coins.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "One quarter, $0.25, can be split into 1 nickel and 2 dimes. Each such splitting will add 2 coins to the combination of coins.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "17 q + 1 n + 2 d = 4.50, count of 20 coins;\r \n" ); document.write( "\n" ); document.write( "16 q + 2 n + 4 d = 4.50, count of 22 coins;\r \n" ); document.write( "\n" ); document.write( "Keep going like this and find: \n" ); document.write( "13 q +5 n + 10 d = 4.50, 28 coins.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------- \n" ); document.write( "COMBINATION: \n" ); document.write( "13 quarters \n" ); document.write( "5 nickels \n" ); document.write( "10 dimes \n" ); document.write( "---------------------- \n" ); document.write( " |