document.write( "Question 1070031: find the sum of all 5 digit numbers that can be formed by using the digits 2,3,5,7 and 8, where each of these digits appears in each number. \n" ); document.write( "
Algebra.Com's Answer #685163 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Suppose you had them all lined up in a column to add:\r\n" ); document.write( "\r\n" ); document.write( " 23578\r\n" ); document.write( " 23587\r\n" ); document.write( " 23758\r\n" ); document.write( " 23785\r\n" ); document.write( " 23857\r\n" ); document.write( " 23875\r\n" ); document.write( " 25378\r\n" ); document.write( " ...\r\n" ); document.write( " 85732\r\n" ); document.write( " 87235\r\n" ); document.write( " 87253\r\n" ); document.write( " 87325\r\n" ); document.write( " 87352\r\n" ); document.write( " 87523\r\n" ); document.write( " +87532\r\n" ); document.write( "=======\r\n" ); document.write( "\r\n" ); document.write( "There are 5!=120 numbers to be added. One 5th of\r\n" ); document.write( "the numbers in each column are 2's, one-fifth are 3's,\r\n" ); document.write( "and so on to one-fifth are 8's, So since one-fifth of\r\n" ); document.write( "120 is 24, the sum of each column is \r\n" ); document.write( "\r\n" ); document.write( "24*(2+3+5+7+8) = 24*(25) = 600\r\n" ); document.write( "\r\n" ); document.write( "So there are \r\n" ); document.write( "\r\n" ); document.write( "600 ten-thousands +\r\n" ); document.write( "600 thousands +\r\n" ); document.write( "600 hundreds +\r\n" ); document.write( "600 tens +\r\n" ); document.write( "600 ones\r\n" ); document.write( "\r\n" ); document.write( "or\r\n" ); document.write( "\r\n" ); document.write( " 6000000 +\r\n" ); document.write( " 600000 +\r\n" ); document.write( " 60000 +\r\n" ); document.write( " 6000 +\r\n" ); document.write( " 600 \r\n" ); document.write( "========\r\n" ); document.write( " 6666600\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |