document.write( "Question 1070052: The circumference of a rectangle with sides a and b is 100 cm. If a is shortened by 5 cm and lengthened b by 6 cm, the surface area is reduced by 60 cm2.
\n" ); document.write( "Calculate the lengths of sides a and b.
\n" ); document.write( "

Algebra.Com's Answer #685141 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
That should be \"perimeter\" of the rectangle.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"a%2Bb%2Ba%2Bb=100\"
\n" ); document.write( "\"2a%2B2b=100\"
\n" ); document.write( "\"a%2Bb=50\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"%28a-5%29%28b%2B6%29\", this area is reduced by 60 cm-squared.
\n" ); document.write( "-
\n" ); document.write( "\"ab-%28a-5%29%28b%2B6%29=60\"
\n" ); document.write( "\"%2850-b%29b-%2850-b-5%29%28b%2B6%29=60\", substituted for a;
\n" ); document.write( "\"50b-b%5E2-%2845-b%29%28b%2B6%29=60\"
\n" ); document.write( "\"50b-b%5E2-%2845b-b%5E2%2B45%2A6-6b%29=60\"
\n" ); document.write( "\"50b-b%5E2-45b%2Bb%5E2-45%2A6%2B6b=60\"
\n" ); document.write( "\"50b-45b%2B6b-b%5E2%2Bb%5E2-270=60\"
\n" ); document.write( "\"11b-270=60\"
\n" ); document.write( "\"11b=60%2B270\"
\n" ); document.write( "\"11b=330\"
\n" ); document.write( "\"b=%2833%2A10%29%2F11\"
\n" ); document.write( "\"highlight%28b=30%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Finding a:
\n" ); document.write( "\"a%2Bb=50\"
\n" ); document.write( "\"a=50-b\"
\n" ); document.write( "\"a=50-30\"
\n" ); document.write( "\"highlight%28a=20%29\"
\n" ); document.write( "
\n" );