document.write( "Question 1070040: Use the properties of exponential and logarithmic functions to solve each
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Algebra.Com's Answer #685136 by Edwin McCravy(20086)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"system%28-2%5E%2810-x%29%2By+=+0%2C+y+=+8%5E%28x%2B2%29%29\"\r\n" );
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document.write( "The second equation is solved for y, so substitute\r\n" );
document.write( "8x+2 for y in the first equation:\r\n" );
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document.write( "\"-2%5E%2810-x%29%2B8%5E%28x%2B2%29=0\"\r\n" );
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document.write( "Add 210-x to both sides:\r\n" );
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document.write( "\"8%5E%28x%2B2%29=2%5E%2810-x%29\"\r\n" );
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document.write( "Write 8 as 23\r\n" );
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document.write( "\"%282%5E3%29%5E%28x%2B2%29=2%5E%2810-x%29\"\r\n" );
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document.write( "Remove the parentheses on the left by multiplying the\r\n" );
document.write( "exponents:\r\n" );
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document.write( "\"2%5E%283x%2B6%29=2%5E%2810-x%29\"\r\n" );
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document.write( "Now we use the principle that \r\n" );
document.write( "if BP = BQ, then P = Q\r\n" );
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document.write( "\"3x%2B6=10-x\"\r\n" );
document.write( "\"4x=4\"\r\n" );
document.write( "\"x=1\"\r\n" );
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document.write( "Substitute in \r\n" );
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document.write( "\"y+=+8%5E%28x%2B2%29\"\r\n" );
document.write( "\"y+=+8%5E%281%2B2%29\"\r\n" );
document.write( "\"y+=+8%5E3\"\r\n" );
document.write( "\"y=512\"\r\n" );
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document.write( "Answer: (x,y) = (1,512)\r\n" );
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document.write( "Edwin
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