document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1070036>Question 1070036</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help factor this 10cx -30c -20x +60. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #685127 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=685127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The Greatest Common Divisor is 10:<BR>\n" );
document.write( "10 goes into 10 once, into 30 three times, into 20 twice, and into 60 six times.<BR>\n" );
document.write( "So factor the 10 out:<BR>\n" );
document.write( "10(cx-3c-2x+6)<BR>\n" );
document.write( "Now factor by grouping:<BR>\n" );
document.write( "cx-3c-2x+6 = (cx-2x)- 3(c-2) <BR>\n" );
document.write( "note here the change in sign. The result is correct: <BR>\n" );
document.write( "-3c = -3*c = -3c and -3*-2 = +6<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Next, factor the x out of the first two terms, and 3 out of the other two:<BR>\n" );
document.write( "10x(c-2)-3(c-2)<BR>\n" );
document.write( "Finally, what other common terms do we have? We have -2. Factor it out and rearrange the equation:<BR>\n" );
document.write( "10(c-2)(x-3)<BR>\n" );
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document.write( "Is this correct? Let's FOIL it (First, Outer, Inner, Last<BR>\n" );
document.write( "10(c*x+c-3-2*x-2*-3) = 10(cx-3c-2x+6) = 10cx-30c-20x+60 Correct<BR>\n" );
document.write( ":<BR>\n" );
document.write( "John<BR>\n" );
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