document.write( "Question 1069908: In Trapezium PQRS, the side PQ and SR are parallel. Angle RSP is 120 and RS=SP= 1/3 PQ. what is the size of angle PQR. \n" ); document.write( "
Algebra.Com's Answer #685103 by KMST(5328)\"\" \"About 
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Since \"PQ\" and \"RS\" are parallel,
\n" ); document.write( "angles \"RSP\" and \"SPQ\" are supplementary.
\n" ); document.write( "So, the measure of angle \"SPQ\" is
\n" ); document.write( "\"180%5Eo-120%5Eo=60%5Eo\" .
\n" ); document.write( "Below I drew \"PQRS\" .
\n" ); document.write( "Since \"RS=PS=%281%2F3%29PQ\" ,
\n" ); document.write( "I added two extra points on \"PQ\"
\n" ); document.write( "points \"T\" and \"U\" ,
\n" ); document.write( "so that \"RS=PS=PT=TU=UQ\" .
\n" ); document.write( "I also added some green lines
\n" ); document.write( "connecting the new points to \"R\" and \"S\" .
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\n" ); document.write( "As you see in the drawing,
\n" ); document.write( "there are three equilateral triangles,
\n" ); document.write( "and all green sides are congruent with
\n" ); document.write( "\"RS\" , \"PS\" , \"PT\" , \"TU\" , and \"UQ\" .
\n" ); document.write( "That makes triangle \"QUR\" isosceles.
\n" ); document.write( "Since vertex angle QUR is supplementary
\n" ); document.write( "to \"60%5Eo\" angle \"TUR\" ,
\n" ); document.write( "angle \"QUR\" measures \"180%5Eo-60%5Eo=120%5Eo\" ,
\n" ); document.write( "and the base angles, \"PQR=UQR\" and \"QRU\" ,
\n" ); document.write( "measure \"%28180%5Eo-120%5Eo%29%2F2=highlight%2830%5Eo%29\" .
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\n" ); document.write( "MORE DETAILED EXPLANATION:
\n" ); document.write( "Triangle \"PTS\" is an equilateral triangle,
\n" ); document.write( "because it has congruent sides \"PT\" and \"PS\"
\n" ); document.write( "flanking a \"60%5Eo\" angle.
\n" ); document.write( "That makes \"TS=PS=%22...%22\" ,
\n" ); document.write( "and makes the measures of angles \"PST\" and \"TSR%7D%7D+%7B%7B%7B60%5Eo\" .
\n" ); document.write( "That,in turn, makes triangle \"RST\" equilateral.
\n" ); document.write( "You can figure out that triangle \"TUR\"
\n" ); document.write( "is equilateral too.
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