document.write( "Question 1069873: A Car A left City X, traveling at an average of 50 miles per hour. Two hours later, a Car B left City X, traveling on the same road at an average velocity of 70 miles per hour. When will the Car B catch up to the Car A? How far will each car have traveled? \n" ); document.write( "

Algebra.Com's Answer #684978 by josgarithmetic(39617) $\"\"$ $\"About$

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document.write( "CAR           SPEED      TIME     DISTANCE\r\n" );
document.write( "A              50        t+2       d\r\n" );
document.write( "B              70         t        d\r\n" );
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\n" ); document.write( "\n" ); document.write( "t, how much time for B to catchup with A
\n" ); document.write( "d, distance traveled when catchup occurs\r
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\n" ); document.write( "\n" ); document.write( "RT=D rule gives this system of equations:
\n" ); document.write( " $\"system%2850%28t%2B2%29=d%2C70t=d%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "The first question can use the equating of d.
\n" ); document.write( " $\"50%28t%2B2%29=70t\"$
\n" ); document.write( " $\"5t%2B10=7t\"$
\n" ); document.write( " $\"10=2t\"$
\n" ); document.write( " $\"highlight%28t=5%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Use that to find the value for d. \n" ); document.write( "

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