document.write( "Question 94091This question is from textbook algebra 2
\n" ); document.write( ": two planes left an airport at noon. one flew east at a certain speed and the other flew west at twice the speed. the planes were 2700 mi apart in 3 h. how fast was each plane flying? \n" ); document.write( "
Algebra.Com's Answer #68497 by checkley75(3666)\"\" \"About 
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3X+3X*2=2700
\n" ); document.write( "3X+6X=2700
\n" ); document.write( "9X=2700
\n" ); document.write( "X=2700/9
\n" ); document.write( "X=300 MPH FOR THE SLOWER PLANE
\n" ); document.write( "2X=600 FOR THE FASTER PLANE
\n" ); document.write( "PROOF
\n" ); document.write( "3*300+6*300=2700
\n" ); document.write( "900+1800=2700
\n" ); document.write( "2700=2700
\n" ); document.write( "
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