document.write( "Question 1069802: Suppose 44 pints of aa 13% alcohol solution is mixed with 66 pints of aa 60% alcohol solution. What is the concentration of alcohol in the new 10-pint mixture?
\n" );
document.write( "The concentration of alcohol in the new 10-pint mixture is?\r
\n" );
document.write( "\n" );
document.write( "How many ounces of a 15% alcohol solution must be mixed with 44 ounces of a 20 % alcohol solution to make a 19 %19% alcohol solution?
\n" );
document.write( "The amount of 15 % alcohol solution is
\n" );
document.write( "? \n" );
document.write( "
Algebra.Com's Answer #684935 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Suppose 44 pints of aa 13% alcohol solution is mixed with 66 pints of aa 60% alcohol solution. \n" ); document.write( " What is the concentration of alcohol in the new 10-pint mixture? \n" ); document.write( "The concentration of alcohol in the new 10-pint mixture is? \n" ); document.write( ": \n" ); document.write( "let x = the percent concentration of the new mixture in decimal form \n" ); document.write( ".13(44) + .60(66) = x(44 + 66) \n" ); document.write( "5.72 + 39.6 = 110x \n" ); document.write( "45.32 = 110x \n" ); document.write( "x = 45.32/110 \n" ); document.write( "x = .416 which is 41.6% \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "How many ounces of a 15% alcohol solution must be mixed with 44 ounces of a 20 % alcohol solution to make a 19 %19% alcohol solution? \n" ); document.write( "The amount of 15 % alcohol solution is \n" ); document.write( ".15x + .20(44) = .19(44+x)\r \n" ); document.write( "\n" ); document.write( ".15x + 8.8 = 8.36 + .19x \n" ); document.write( "8.8 - 8.36 = .19x - .15x \n" ); document.write( ".44 = .04x \n" ); document.write( "x = .44/.04 \n" ); document.write( "x = 11 oz of 15% solution \n" ); document.write( " |