document.write( "Question 1069802: Suppose 44 pints of aa 13​% alcohol solution is mixed with 66 pints of aa 60​% alcohol solution. What is the concentration of alcohol in the new 10​-pint ​mixture?
\n" ); document.write( "The concentration of alcohol in the new 10​-pint mixture is?\r
\n" ); document.write( "\n" ); document.write( "How many ounces of a 15% alcohol solution must be mixed with 44 ounces of a 20 % alcohol solution to make a 19 %19% alcohol​ solution?
\n" ); document.write( "The amount of 15 % alcohol solution is
\n" ); document.write( "?
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Algebra.Com's Answer #684935 by ankor@dixie-net.com(22740)\"\" \"About 
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Suppose 44 pints of aa 13​% alcohol solution is mixed with 66 pints of aa 60​% alcohol solution.
\n" ); document.write( " What is the concentration of alcohol in the new 10​-pint ​mixture?
\n" ); document.write( "The concentration of alcohol in the new 10​-pint mixture is?
\n" ); document.write( ":
\n" ); document.write( "let x = the percent concentration of the new mixture in decimal form
\n" ); document.write( ".13(44) + .60(66) = x(44 + 66)
\n" ); document.write( "5.72 + 39.6 = 110x
\n" ); document.write( "45.32 = 110x
\n" ); document.write( "x = 45.32/110
\n" ); document.write( "x = .416 which is 41.6%
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\n" ); document.write( ":
\n" ); document.write( "How many ounces of a 15% alcohol solution must be mixed with 44 ounces of a 20 % alcohol solution to make a 19 %19% alcohol​ solution?
\n" ); document.write( "The amount of 15 % alcohol solution is
\n" ); document.write( ".15x + .20(44) = .19(44+x)\r
\n" ); document.write( "\n" ); document.write( ".15x + 8.8 = 8.36 + .19x
\n" ); document.write( "8.8 - 8.36 = .19x - .15x
\n" ); document.write( ".44 = .04x
\n" ); document.write( "x = .44/.04
\n" ); document.write( "x = 11 oz of 15% solution
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