document.write( "Question 1069813: A shop that sells nuts has one mixture that is 30% pecans and
\n" ); document.write( "70% peanuts. A second mixture is 40% pecans and 60% peanuts.
\n" ); document.write( "The manager wants to make a mixture that is 38% pecans. She
\n" ); document.write( "wants to use 25 ounces more of the second mixture than the
\n" ); document.write( "first. How many ounces of each mixture should she use?\r
\n" ); document.write( "\n" ); document.write( "Thanks!
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Algebra.Com's Answer #684932 by addingup(3677)\"\" \"About 
You can put this solution on YOUR website!
Let's call the weight of the first mixture x. Thus, the weight of the second mixture will be x+25, since you want to use 25oz. more of the second mixture than the first.
\n" ); document.write( "So, the total weight for our final mixture will be:
\n" ); document.write( "x+x+25 = 2x+25
\n" ); document.write( ":
\n" ); document.write( "Now for the weight of the pecans:
\n" ); document.write( "first mixture: 30% pecans = 0.3x.
\n" ); document.write( "second mixture:40% pecans = 0.4(x+25)
\n" ); document.write( "Lastly, we are looking for a mix with 38% pecans = 0.38(x+x+25)= 0.38(2x+25)
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\n" ); document.write( "Put it all together:
\n" ); document.write( "0.3x+0.4(x+25) = 0.38(2x+25)
\n" ); document.write( "0.3x+0.4x+10 = 0.76x+9.5
\n" ); document.write( "0.7x = 0.76x-0.5 subtract 7x and add 0.5 to both sides
\n" ); document.write( "0.5 = 0.06x flip the equation, it looks better with the variable x on the left
\n" ); document.write( "0.06x = 0.5 divide both sides by 0.06
\n" ); document.write( "x = 8.33 So this is the weight of the first mixture. The second mixture, the problem says, will be 25 oz. more: 8.33+25 = 33.33oz.
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\n" ); document.write( "Additional info:
\n" ); document.write( "What will be the total weight of the final mixture? 8.33+33.33 = 41.66 ounces.
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\n" ); document.write( "Happy learning,
\n" ); document.write( "John
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