document.write( "Question 94082This question is from textbook Geometry
\n" ); document.write( ": Two angles are supplementary. One angle measures 12degrees more than the other. Find the measures of the angles. \n" ); document.write( "
Algebra.Com's Answer #68490 by praseenakos@yahoo.com(507)\"\" \"About 
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Question:\r
\n" ); document.write( "\n" ); document.write( "Two angles are supplementary. One angle measures 12degrees more than the other. Find the measures of the angles.\r
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\n" ); document.write( "\n" ); document.write( "If the two angles add to 180°, we say they \"Supplement\" each other. \r
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\n" ); document.write( "\n" ); document.write( "Assume that one angle = X degrees.\r
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\n" ); document.write( "\n" ); document.write( "The other angle = X + 12 degrees ( it is given that other angle is 12 degrees more than the first one)\r
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\n" ); document.write( "\n" ); document.write( "Since supplementary angles add to 180 degrees, we can write,\r
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\n" ); document.write( "\n" ); document.write( "X + ( X + 12 ) = 180\r
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\n" ); document.write( "\n" ); document.write( "==> X + X + 12 = 180\r
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\n" ); document.write( "\n" ); document.write( "==> 2X + 12 = 180\r
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\n" ); document.write( "\n" ); document.write( "Subtract 12 from both sides \r
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\n" ); document.write( "\n" ); document.write( "==> 2X + 12 - 12 = 180 - 12\r
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\n" ); document.write( "\n" ); document.write( "==> 2X = 168 \r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "==> \"+2X%2F2+=+168%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "==> X = 84\r
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\n" ); document.write( "\n" ); document.write( "That is one angle is 84 degrees\r
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\n" ); document.write( "\n" ); document.write( "So the other angle is X +12 = 84 + 12 = 96 degrees.\r
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\n" ); document.write( "\n" ); document.write( "So the supplementary angles are, \"+84+\" and \"96\"\r
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\n" ); document.write( "\n" ); document.write( "Hope you found the explanation useful.\r
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\n" ); document.write( "\n" ); document.write( "Regards.\r
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\n" ); document.write( "\n" ); document.write( "Praseena.\r
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