document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13593>Question 13593</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One half of a number increased by 16 is four less than two thirds of the number.find the number.\r<BR>\n" );
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document.write( "It is straight out of the book please help me.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6849 by </B><A HREF=/tutors/aboutme.mpl?userid=LilSkittleMd><B>LilSkittleMd(119)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LilSkittleMd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation for this problem is 1/2x+16=4-2/3x<BR>\n" );
document.write( "Solve the equation:<BR>\n" );
document.write( "The x's need to be on one side and the numbers on the other, add 2/3x to both sides of the equation<BR>\n" );
document.write( "1/2x+2/3x+16=4<BR>\n" );
document.write( "Now subtract 16 from both sides of the equation<BR>\n" );
document.write( "1/2x+2/3x=-12 (Add the two fractions together)<BR>\n" );
document.write( "7/6x=-12 (Divide both sides of the equation by 7/6)<BR>\n" );
document.write( "x=-72/7<BR>\n" );
document.write( "The number for this equation is -72/7<BR>\n" );
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