document.write( "Question 1069703: Divide 243 into 3 parts such that half of the first part,one-third of the second part and one-fourth of the third part are all equal. \n" ); document.write( "

Algebra.Com's Answer #684882 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "First part of the condition says \r\n" );
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document.write( "x + y + z = 243,     (1)   \r\n" );
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document.write( "where x is the first quantity, y is the second and z is the third.\r\n" );
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document.write( "Second part of the condition gives these equalities\r\n" );
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document.write( " = ,       (2)\r\n" );
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document.write( " =         (3)\r\n" );
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document.write( "From (2),  y = ,  z =  =  = 2x. \r\n" );
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document.write( "Substitute it into (3), and you will get\r\n" );
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document.write( " = 243,   or\r\n" );
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document.write( "4.5x = 243.\r\n" );
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document.write( "x =  = 54.\r\n" );
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document.write( "Then  y =  = 81  and  z = 2x = 108.\r\n" );
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