document.write( "Question 1069711: Question: A basketball player has a 50% chance of making each free throw. What is the probability that the player makes at least two out of six free throws?\r
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document.write( "My Attempt: I first found (1/2)^6 , because we have 6 \"spots\" or free throws. \r
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document.write( "Since finding 2,4,5,6 all work, I found in how many combinations can he make each of those events...15+40+15+6+1=77... My answer then would be 77/64. But the probability has to be less than 1....Where might have I went wrong?
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document.write( "Thanks in Advance!\r
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Algebra.Com's Answer #684858 by Fombitz(32388) You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So then, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "At least two means two through six, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |