document.write( "Question 1069711: Question: A basketball player has a 50% chance of making each free throw. What is the probability that the player makes at least two out of six free throws?\r
\n" ); document.write( "\n" ); document.write( "My Attempt: I first found (1/2)^6 , because we have 6 \"spots\" or free throws. \r
\n" ); document.write( "\n" ); document.write( "Since finding 2,4,5,6 all work, I found in how many combinations can he make each of those events...15+40+15+6+1=77... My answer then would be 77/64. But the probability has to be less than 1....Where might have I went wrong?
\n" ); document.write( "Thanks in Advance!\r
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Algebra.Com's Answer #684858 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"P%28X%29=C%286%2CX%29%2A%281%2F2%29%5EX%2A%281%2F2%29%5E%286-X%29\"
\n" ); document.write( "\"P%28X%29=C%286%2CX%29%281%2F2%29%5E6\"
\n" ); document.write( "\"P%28X%29=C%286%2CX%29%2F64\"
\n" ); document.write( "So then,
\n" ); document.write( "\"P%280%29=1%2F64\"
\n" ); document.write( "\"P%281%29=6%2F64\"
\n" ); document.write( "\"P%282%29=15%2F64\"
\n" ); document.write( "\"P%283%29=20%2F64\"<--- You had 40, that was your mistake.
\n" ); document.write( "\"P%284%29=15%2F64\"
\n" ); document.write( "\"P%285%29=6%2F64\"
\n" ); document.write( "\"P%286%29=1%2F64\"
\n" ); document.write( "At least two means two through six,
\n" ); document.write( "\"P=%2815%2B20%2B15%2B6%2B1%29%2F64\"
\n" ); document.write( "\"P=57%2F64\"
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