document.write( "Question 1069398: Suppose Z is a standard normal random variable.
\n" ); document.write( "If P(-z < Z < z) = 0.5588, find z.
\n" ); document.write( "Find P( -2.46 < Z < -0.16)
\n" ); document.write( "Some did it but wasn't right
\n" ); document.write( "Please help
\n" ); document.write( "Thank you so much
\n" ); document.write( "

Algebra.Com's Answer #684768 by MathTherapy(10555)\"\" \"About 
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Suppose Z is a standard normal random variable.
\n" ); document.write( "If P(-z < Z < z) = 0.5588, find z.
\n" ); document.write( "Find P( -2.46 < Z < -0.16)
\n" ); document.write( "Some did it but wasn't right
\n" ); document.write( "Please help
\n" ); document.write( "Thank you so much
\n" ); document.write( "
As P(- z < Z < z) = 0.5588, .5588 is the center interval beneath the bell curve
\n" ); document.write( "Therefore, to the left of the P(Z), probability = 1 - .5588, or .4412
\n" ); document.write( "This probability represents the TOTAL probabilities of the left and right tails
\n" ); document.write( "We now take the AVERAGE of this probability to get \"matrix%281%2C3%2C+.4412%2F2%2C+%22=%22%2C+.2206%29\"
\n" ); document.write( "Using a calculator, excel, or other applications, you'll find that the z-score that represents a probability (to the left of the curve) of .2206 is: - 0.77,
\n" ); document.write( "which means that: . This is close enough. \n" ); document.write( "
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