document.write( "Question 1069540: Debbie is one year older than Dave. James is twice as old as Dave. Joelle is twice as old as Debbie. Altogether their ages total 33. Find each person's age (let x=Dave's age) \n" ); document.write( "
Algebra.Com's Answer #684757 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! They want you to use \n" ); document.write( "so they only want 1 unkown in the equations. \n" ); document.write( "---------------------- \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "(3) \n" ); document.write( "(4) \n" ); document.write( "(5) \n" ); document.write( "------------------------------------------ \n" ); document.write( "(5) \n" ); document.write( "(5) \n" ); document.write( "(5) \n" ); document.write( "(5) \n" ); document.write( "(5) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "and \n" ); document.write( "(3) \n" ); document.write( "(3) \n" ); document.write( "and \n" ); document.write( "(4) \n" ); document.write( "(4) \n" ); document.write( "--------------------------- \n" ); document.write( "Dave's age is 5 \n" ); document.write( "Jame's age is 10 \n" ); document.write( "Debbie's age is 6 \n" ); document.write( "Joelle's age is 12 \n" ); document.write( "---------------------- \n" ); document.write( "check: \n" ); document.write( "(5) \n" ); document.write( "(5) \n" ); document.write( "(5) \n" ); document.write( "OK \n" ); document.write( " |