document.write( "Question 1069519: A recent report indicated that 67% of teens 12 to 19 play a video game online at least once a week. How large of a sample would a researcher need to estimate the true proportion of teens 12 to 19 who play a video game online at least once a week within 3% with a 95% confidence level?\r
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document.write( "a) 844
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document.write( "b) 4489
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document.write( "c) 944
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document.write( "d) 4144 \n" );
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Algebra.Com's Answer #684699 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! half of the interval for a one sample proportion is z(0.975)sqrt{p*(1-p)/n}, and it equals .03 \n" ); document.write( ".03=1.96*sqrt {(.67)(.33)/n} \n" ); document.write( "square both sides \n" ); document.write( ".0009=3.8416*(.67*.33)/n \n" ); document.write( ".0009n=0.8494 (I would not round but keep it on the calculator unrounded until the end. \n" ); document.write( "divide by .0009 \n" ); document.write( "943.75. Round upward to 944. \n" ); document.write( "C. \n" ); document.write( " |