document.write( "Question 94054This question is from textbook geometry
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Algebra.Com's Answer #68468 by praseenakos@yahoo.com(507)\"\" \"About 
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Question:\r
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\n" ); document.write( "\n" ); document.write( "If the two angles add to 180°, we say they \"Supplement\" each other.\r
\n" ); document.write( "\n" ); document.write( "Here measure of T is 20 more than four times its supplement\r
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\n" ); document.write( "\n" ); document.write( "Assume that the supplement of T is = X\r
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\n" ); document.write( "\n" ); document.write( "Four times X = 4X\r
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\n" ); document.write( "\n" ); document.write( "20 more than 4X = 4X + 20\r
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\n" ); document.write( "\n" ); document.write( "So T = 4X + 20\r
\n" ); document.write( "\n" ); document.write( "Since these angles are supplementary, X + T = 180\r
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\n" ); document.write( "\n" ); document.write( "==> X + (4X + 20) = 180\r
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\n" ); document.write( "\n" ); document.write( "==> X + 4X + 20 = 180\r
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\n" ); document.write( "\n" ); document.write( "==> 5X + 20 = 180\r
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\n" ); document.write( "\n" ); document.write( "Subtract 20 from both sides....\r
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\n" ); document.write( "\n" ); document.write( "==> 5X + 20 - 20 = 180 - 20\r
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\n" ); document.write( "\n" ); document.write( "==> 5X = 160\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 5\r
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\n" ); document.write( "\n" ); document.write( "==> \"++5X%2F5+=+160%2F5+\"\r
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\n" ); document.write( "\n" ); document.write( "==> X = 32\r
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\n" ); document.write( "\n" ); document.write( "So , T = 4X + 20 = 4 * 32 + 20 = 128 + 20 = 148 degrees.\r
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\n" ); document.write( "\n" ); document.write( "So measure of T = 148 degrees.\r
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\n" ); document.write( "\n" ); document.write( "Hope you found the explanation useful.\r
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\n" ); document.write( "\n" ); document.write( "Regards.\r
\n" ); document.write( "\n" ); document.write( "Praseena.\r
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