document.write( "Question 1069395: Find the global maximum and minimum for the function on the closed interval.\r
\n" ); document.write( "\n" ); document.write( "18x^1/3 -6x
\n" ); document.write( "on the interval -1 less or equal to x less or equal to 8\r
\n" ); document.write( "\n" ); document.write( "Enter the exact answers. Enter the values for x in increasing order.\r
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Algebra.Com's Answer #684654 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Graphing,
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\n" ); document.write( "Using calculus,
\n" ); document.write( "\"y=18x%5E%281%2F3%29-6x\"
\n" ); document.write( "\"dy%2Fdx=6%2Fx%5E%282%2F3%29-6\"
\n" ); document.write( "Setting the derivative to zero,
\n" ); document.write( "\"6%2Fx%5E%282%2F3%29-6=0\"
\n" ); document.write( "\"6%2Fx%5E%282%2F3%29=6\"
\n" ); document.write( "\"x%5E%282%2F3%29=1\"
\n" ); document.write( "\"x=1\"
\n" ); document.write( "Since the second derivative is negative, when \"x=1\", this value is a maximum.
\n" ); document.write( "Find the minimum value by checking the endpoints.
\n" ); document.write( "\"f%28-1%29=-18%2B6=-12\"
\n" ); document.write( "\"f%288%29=36-48=-12\"\r
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