document.write( "Question 1069403: The function Q (t) = 0.003t^2 – 0.625t + 25 represents the amount of energy in a battery after t minutes of use.\r
\n" ); document.write( "\n" ); document.write( "(a) State the amount of energy held by the battery immediately before it was used.\r
\n" ); document.write( "\n" ); document.write( "(c) Given that Q (10) = 19.05, find the average amount of energy produced per minute for the interval 10 ≤ t ≤ 20.\r
\n" ); document.write( "\n" ); document.write( "(d) Calculate the number of minutes it takes for the energy to reach zero.
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Algebra.Com's Answer #684637 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
(a)
\n" ); document.write( "At \"+t+=+0+\"
\n" ); document.write( "\"+Q%28t%29+=+.003t%5E2+-+.625t+%2B+25+\"
\n" ); document.write( "\"+Q%28t%29+=+.003%2A0%5E2+-+.625%2A0+%2B+25+\"
\n" ); document.write( "\"+Q%280%29+=+25+\"
\n" ); document.write( "---------------------
\n" ); document.write( "(b)
\n" ); document.write( "\"+Q%2810%29+=+19.05+\"
\n" ); document.write( "\"+Q%2820%29+=+.003%2A20%5E2+-+.625%2A20+%2B+25+\"
\n" ); document.write( "\"+Q%2820%29+=+.003%2A400+-+12.5+%2B+25+\"
\n" ); document.write( "\"+Q%2820%29+=+1.2+-+12.5+%2B+25+\"
\n" ); document.write( "\"+Q%2820%29+=+13.7+\"
\n" ); document.write( "\"+13.7+-+19.05+=+-5.35+\"
\n" ); document.write( "units of energy used in \"+20+-+10+=+10+\" min
\n" ); document.write( "\"+5.35%2F10+=+.535+\" average energy/min
\n" ); document.write( "produced for \"+10+%3C=+t+%3C=+20+\"
\n" ); document.write( "------------------
\n" ); document.write( "(c)
\n" ); document.write( "\"+Q%28t%29+=+.003t%5E2+-+.625t+%2B+25+\"
\n" ); document.write( "When does \"+Q%28t%29+=+0+\" ?
\n" ); document.write( "\"+0+=+.003t%5E2+-+.625t+%2B+25+\"
\n" ); document.write( "Use quadratic formula
\n" ); document.write( "\"+t+=+%28+-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"+a+=+.003+\"
\n" ); document.write( "\"+b+=+-.625+\"
\n" ); document.write( "\"+c+=+25+\"
\n" ); document.write( "------------------
\n" ); document.write( "\"+t+=+%28+-%28-.625%29+%2B-+sqrt%28+%28-.625%29%5E2+-+4%2A.003%2A25+%29%29%2F%282%2A.003%29+\"
\n" ); document.write( "\"+t+=+%28+.625+%2B-+sqrt%28+.3906+-+.3+%29%29%2F.006+\"
\n" ); document.write( "\"+t+=+%28+.625+%2B-+sqrt%28+.0906+%29%29%2F.006+\"
\n" ); document.write( "\"+t+=+%28+.625+%2B+.301+%29+%2F+.006+\"
\n" ); document.write( "\"+t+=+.926%2F.006+\"
\n" ); document.write( "\"+t+=+154.33+\"
\n" ); document.write( "and
\n" ); document.write( "\"+t+=+%28+.625+-+.301+%29+%2F+.006+\"
\n" ); document.write( "\"+t+=+.324%2F.006+\"
\n" ); document.write( "\"+t+=+54+\"
\n" ); document.write( "---------------
\n" ); document.write( "Here's the plot:
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-5%2C+70%2C+-5%2C+50%2C+.003x%5E2+-+.625x+%2B+25+%29+\"
\n" ); document.write( "This tells me that at \"+t+=+54+\" min the energy is zero
\n" ); document.write( "I can ignore the root \"+t+=+154.33+\"\r
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