document.write( "Question 1069399: $\"12%5E%28x-2%29=20\"$ \r
\n" ); document.write( "\n" ); document.write( "How do you find x?\r
\n" ); document.write( "\n" ); document.write( "I did\r
\n" ); document.write( "\n" ); document.write( " $\"+%28x-2%29log12=20\"$
\n" ); document.write( " $\"+x-2=+%2820%2Flog12%29\"$
\n" ); document.write( " $\"+x=+%2820%2Flog12%29%2B2\"$ \r
\n" ); document.write( "\n" ); document.write( "x=20.5326816 \n" ); document.write( "

Algebra.Com's Answer #684611 by jorel1380(3719) $\"\"$ $\"About$

You can put this solution on YOUR website!
First off, you have to take the logarithm of both sides:
\n" ); document.write( "12^(x-2)=20
\n" ); document.write( "log 12^(x-2)=log 20
\n" ); document.write( "(x-2)log 12=log 20
\n" ); document.write( "x-2=log 20/log 12
\n" ); document.write( "x=(log 20/log 12)+2=3.20557135368 ☺☺☺☺ \n" ); document.write( "

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