document.write( "Question 1069380: The length of a rectangle is 2x-3. The width is x+3. Find the area of the rectangle and solve for x.
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Algebra.Com's Answer #684592 by josgarithmetic(39627)\"\" \"About 
You can put this solution on YOUR website!
You either must be given the area, or you need to assign a variable to it; then you can solve for x.\r
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\n" ); document.write( "\n" ); document.write( "\"A=%282x-3%29%28x%2B3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2-3x%2B6x-9-A=0\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B3x-%28A%2B9%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "If your value for A makes the equation factorable, then use factoring to solve. Otherwise, use general solution for quadratic equation:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-3%2B-+sqrt%283%5E2%2B4%2A2%2A%28A%2B9%29%29%29%2F%282%2A2%29\", from which one of the x values might not be acceptable but the other will be.
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