document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1069244>Question 1069244</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the length of rhombus is 13 cm and the one diagonal is 24 cm . what is the area of the rhombus  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #684521 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=684521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We know that the diagonals of a rhombus bisect each other at right angles, then<BR>\n" );
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document.write( "(24/2)^2 + x^2 = 13^2<BR>\n" );
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document.write( "x^2 = 169 - 144 = 25<BR>\n" );
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document.write( "x = 5<BR>\n" );
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document.write( "therefore the other diagonal is 2(5) = 10<BR>\n" );
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document.write( "Area of rhombus = (10 * 24) / 2 = 120 cm^2<BR>\n" );
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