document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1069254>Question 1069254</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The net income y (in millions of dollars) of Pet Products Unlimited from 1997 to 1999 is given by the equation y = 9x2 + 15x + 52, where x represents the number of years after 1997. Assume this trend continues and predict the year in which Pet Products Unlimited's net income will be $598 million </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #684460 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=684460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9x^2 + 15x + 52 = 598<BR>\n" );
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document.write( "subtract 598 from both sides of =<BR>\n" );
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document.write( "9x^2 + 15x - 546 = 0<BR>\n" );
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document.write( "divide both sides of = by 3<BR>\n" );
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document.write( "3x^2 + 5x - 182 = 0<BR>\n" );
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document.write( "(3x+26) * (x-7) = 0<BR>\n" );
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document.write( "x = -26/3 and x = 7<BR>\n" );
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document.write( "we reject the negative value for x<BR>\n" );
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document.write( "We predict the year to be 1997 + 7 = 2004<BR>\n" );
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