document.write( "Question 1069135: It takes Kenny 1 hour longer than Dennis to shuck a sack of oysters. IF together they shuck a sack of oysters in 45 minutes, then how long would it take each one working alone? \n" ); document.write( "
Algebra.Com's Answer #684382 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! It takes Kenny 1 hour longer than Dennis to shuck a sack of oysters. \n" ); document.write( " IF together they shuck a sack of oysters in 45 minutes, then how long would it take each one working alone? \n" ); document.write( ": \n" ); document.write( "change 45 min to .75 hrs \n" ); document.write( ": \n" ); document.write( "let t = time (in hrs) for Dennis to shuck a sack of oysters \n" ); document.write( "then \n" ); document.write( "(t+1) = time required by Kenny \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 (a sack of shucked oysters) \n" ); document.write( " \n" ); document.write( "multiply by t(t+1), cancel the denominators \n" ); document.write( ".75(t+1) + .75t = t(t+1) \n" ); document.write( ".75t + .75 + .75t = t^2 + t \n" ); document.write( "1.5t + .75 = t^2 + t \n" ); document.write( "0 = t^2 + t - 1.5t - .75 \n" ); document.write( "a quadratic equation \n" ); document.write( "t^2 - .5t - .75 = 0 \n" ); document.write( "using the quadratic formula; a=1; b=-.5; c=-.75, I got \n" ); document.write( "t = -.65 (not a solution) \n" ); document.write( "and \n" ); document.write( "t = 1.15 hrs is Dennis's time alone (that's: 1 + .15(60) = 1 hr 9 min) \n" ); document.write( "then \n" ); document.write( "2.15 hrs is Kenny's time \n" ); document.write( " |