document.write( "Question 1069142: A train averages a speed of 90 miles per hour across the plains and 37.5 miles per hour through the mountains. If a trip of 300 miles took 3 hour and 48 minutes, how much of it was through the mountains? \n" ); document.write( "
Algebra.Com's Answer #684371 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A train averages a speed of 90 miles per hour across the plains and 37.5 miles per hour through the mountains. \n" ); document.write( " If a trip of 300 miles took 3 hour and 48 minutes, how much of it was through the mountains? \n" ); document.write( ": \n" ); document.write( "Let d = distance traveled at 37.5 (thru the mountains) \n" ); document.write( "then \n" ); document.write( "(300-d) = distance traveled at 90 mph \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed \n" ); document.write( "change 3 hr 48 min to hrs: 3 + 48/60 = 3.8 hrs \n" ); document.write( "plain time + mountain time = 3.8 hrs \n" ); document.write( " \n" ); document.write( "Multiply 90*37.5 \n" ); document.write( "3375* \n" ); document.write( "cancel the denominator \n" ); document.write( "37.5(300-d) + 90d = 12825 \n" ); document.write( "11250 - 37.5d + 90d = 12825 \n" ); document.write( "52.5d = 1575 \n" ); document.write( "d = 1575/52.5 \n" ); document.write( "d = 30 mi thru the mountains \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check this, find the distance on the plain \n" ); document.write( "300-30 = 270 mi \n" ); document.write( "Find the actual time at each speed \n" ); document.write( "270/90 = 3 hrs \n" ); document.write( "30/37.5 = .8 hrs \n" ); document.write( "----------------- \n" ); document.write( "total time: 3.8 hrs\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |