document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=93998>Question 93998</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the are of rectangle whose length is twice its width and whose perimeter is equal to that of a square whose area is 1? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68437 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68437\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A square who's area is 1 has a side equal to 1. So, it's perimeter is 4.<BR>\n" );
document.write( "Let L=Length and W=width<BR>\n" );
document.write( "L=2W<BR>\n" );
document.write( "P=2*(L+W) Perimeter formula<BR>\n" );
document.write( "Substitute 2W for L: P=2*(2W+W)=2(3W)=6W <BR>\n" );
document.write( "6W=4<BR>\n" );
document.write( "divide both sides by 6:  W=4/6=2/3<BR>\n" );
document.write( "L=2W=2*2/3=4/3<BR>\n" );
document.write( "Area=L*W=(2/3)*(4/3)=8/9<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );