document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1069126>Question 1069126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help me solve by completing the square to change the form of the function\r<BR>\n" );
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document.write( "f(x) = -2x^2-2x+2\r<BR>\n" );
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document.write( "State the Vertex\r<BR>\n" );
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document.write( "State the Point on the line (x,y) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #684359 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=684359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = -2x^2-2x+2 =-(2x^2+2x-2)<BR>\n" );
document.write( "set equal to 0 and move the constant over.  We are moving +2 over, so it will be negative on the other side<BR>\n" );
document.write( "-(2x^2+2x)=-2<BR>\n" );
document.write( "divide by 2 (could do earlier) to make the leading coefficient 1)<BR>\n" );
document.write( "-(x^2+x)= -1<BR>\n" );
document.write( "take half of the coefficient first power term and square it, adding it to both sides.<BR>\n" );
document.write( "-(x^2+x+(1/4))=-1-1/4<BR>\n" );
document.write( "make the leading signs positive (can do this earlier<BR>\n" );
document.write( "(x^2+x+1/4)=(5/4)<BR>\n" );
document.write( "factor<BR>\n" );
document.write( "(x+(1/2))^2=5/4<BR>\n" );
document.write( "take the square roots of both sides<BR>\n" );
document.write( "x+(1/2)=+/- sqrt (5)/2<BR>\n" );
document.write( "bring the 1/2 over<BR>\n" );
document.write( "x=-1/2+/- sqrt (5)/2 or (-1+/- sqrt (5)/2<BR>\n" );
document.write( "The vertex x-value is -b/2a, where b=-2 and a=-2.  The vertex x is - (-2/-4)=-1/2<BR>\n" );
document.write( "If x= -1/2, f(x)=-2(1/4)+2(1/2)+2=(5/2)<BR>\n" );
document.write( "the vertex is at (-1/2, 5/2)<BR>\n" );
document.write( "a point on the function is (0,2).  Set x equal to 0 for the easiest point to find.<BR>\n" );
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