document.write( "Question 1069121: solve for x: 80x^2-96x+27=0 \n" ); document.write( "
Algebra.Com's Answer #684353 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 80x^2-96x+27=0 \n" ); document.write( "x=(1/160)(96+/- sqrt (96^2-8640); sqrt (9216-8640)=sqrt (576)=24 \n" ); document.write( "x=(1/160)(96+/-24) \n" ); document.write( "x=(1/160)(120), or 3/4 \n" ); document.write( "x=(1/160)(72) or 9/20 \n" ); document.write( "80(9/16)-96(3/4)+27=45-72+27=0 \n" ); document.write( "80(.2025)-96(.45)+27=16.2-43.2+27=0 \n" ); document.write( " |