document.write( "Question 1069121: solve for x: 80x^2-96x+27=0 \n" ); document.write( "
Algebra.Com's Answer #684353 by Boreal(15235)\"\" \"About 
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80x^2-96x+27=0
\n" ); document.write( "x=(1/160)(96+/- sqrt (96^2-8640); sqrt (9216-8640)=sqrt (576)=24
\n" ); document.write( "x=(1/160)(96+/-24)
\n" ); document.write( "x=(1/160)(120), or 3/4
\n" ); document.write( "x=(1/160)(72) or 9/20
\n" ); document.write( "80(9/16)-96(3/4)+27=45-72+27=0
\n" ); document.write( "80(.2025)-96(.45)+27=16.2-43.2+27=0
\n" ); document.write( "\"graph%28300%2C300%2C-2%2C2%2C-10%2C10%2C80x%5E2-96x%2B27%29\"
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