document.write( "Question 1069100: The base of a traingle exceeds the height by 4 feet. If the area is 58.5 square feet, find the length of the base and the height of the triangle. \n" ); document.write( "
Algebra.Com's Answer #684324 by geo_freak(10)\"\" \"About 
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Let's have the length of the height be \"h\".
\n" ); document.write( "The base exceeds the height (h) by 4 feet: h + 4
\n" ); document.write( "The area of the triangle is 58.5 square feet. \r
\n" ); document.write( "\n" ); document.write( "Area of triangle = (b x h) / 2
\n" ); document.write( "58.5 square feet = ((h + 4)(h))/2\r
\n" ); document.write( "\n" ); document.write( "Solve for h
\n" ); document.write( "\"%28%28h%2B4%29%28h%29%29%2F2+=+58.5+square+feet\"
\n" ); document.write( "\"%28h%5E2+%2B+4h%29+%2F+2+=+58.5\"
\n" ); document.write( "\"2%28%28h%5E2+%2B+4h%29+%2F+2%29+=+2%2858.5%29\"
\n" ); document.write( "\"2h%5E2+%2B+8h+=+117\"
\n" ); document.write( "\"2h%5E2+%2B+8h+-+117+=+0\"
\n" ); document.write( "\"h+=+5+sqrt%285%2F2%29+-+2\"\r
\n" ); document.write( "\n" ); document.write( "So base = \"4+%2B+%285+sqrt%285%2F2%29+-+2%29\" and height = \"5+sqrt%285%2F2%29+-+2\"\r
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