document.write( "Question 1069023: A group of twenty-five coins, whose total value is $2.75, is composed of nickels, dimes, and quarters. If the nickels were dimes, the dimes were quarters, and the quarters were nickels, the total would be
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Algebra.Com's Answer #684265 by ikleyn(52810) $\"\"$ $\"About$

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document.write( "Let n = #nickels, d = #dimes, q = #quarters.\r\n" );
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document.write( "Then your equations are\r\n" );
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document.write( "  n +   d +   q = 25,     (1)\r\n" );
document.write( " 5n + 10d + 25q = 275     (2)    (cents)\r\n" );
document.write( "10n + 25d +  5q = 375.    (3)\r\n" );
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document.write( "To solve it, express n = 25 - d - q from (1), then substitute it into (2) and (3), replacing n in each of these two equations. You will get\r\n" );
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document.write( " 5*(25 - d - q) + 10d + 25q = 275     (2')\r\n" );
document.write( "10*(25 - d - q) + 25d +  5q = 375.    (3').\r\n" );
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document.write( "Simplify to get the standard form of a 2x2 system.\r\n" );
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document.write( "Then solve it by any method you know to get n = 10, d = 10 and q = 5.\r\n" );
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document.write( "It is just technique.\r\n" );
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