document.write( "Question 1068992: The tangent line to the graph of y = h(x) at the point (-1, 7) passes through the point (9, 9). Find h(-1) and h'(-1). \n" ); document.write( "
Algebra.Com's Answer #684250 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! h(-1)=7 \n" ); document.write( "point slope formula y-y1=m(x-x1), m slope, (x1,y1) point \n" ); document.write( "slope is 2/10=1/5 \n" ); document.write( "y-9=(1/5)(x-9)=(1/5)x-(9/5) \n" ); document.write( "y=(1/5)x+(36/5) the equation of the tangent line. \n" ); document.write( "The slope of the tangent line is the derivative of h(x). That is the slope of the line which is (1/5). The previous -1/5 was in error. \n" ); document.write( " |