document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1069009>Question 1069009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> which set the ratios should be used to find the mass of potassuim (K) in 455 grams of KCN?\r<BR>\n" );
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document.write( " A. K/455=39/65\r<BR>\n" );
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document.write( " B. K/39=12/65\r<BR>\n" );
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document.write( "C. K/455=65/39\r<BR>\n" );
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document.write( " D. 39/KCN=14/455 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #684242 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=684242\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Weight of K is to the whole weight has the MW of K is to the whole MW.<BR>\n" );
document.write( "That would be A<BR>\n" );
document.write( "39 x455=65K<BR>\n" );
document.write( "divide by 65 both sides<BR>\n" );
document.write( "39 x 7 is K.\r<BR>\n" );
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document.write( "KCN has MW of 65<BR>\n" );
document.write( "455 gms is 7 x 65<BR>\n" );
document.write( "Therefore, the mass of potassium is 7x39.<BR>\n" );
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