document.write( "Question 1068972: Mandy begins bicycling west at 20moh. Liz leaves from the same pint 1 hour later bicycling west at 30mph. When will she catch up with mandy?
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document.write( "A: define variable
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document.write( "B: make a chart
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document.write( "C:set the distance equal to one another (they travel the same diatance) and solve the equation for t. \n" );
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Algebra.Com's Answer #684239 by addingup(3677)![]() ![]() You can put this solution on YOUR website! When? = time = x \n" ); document.write( "Mandy: 20x \n" ); document.write( "Liz: 30(x-1) \n" ); document.write( "20x = 30(x-1) \n" ); document.write( "20x = 30x-30 add 30 and subtract 20x on both sides: \n" ); document.write( "10x = 30 \n" ); document.write( "x = 3 they will meet 3 hours after Mandy left, 2 hours after Liz left \n" ); document.write( "------------------------------------- \n" ); document.write( "Check: \n" ); document.write( "20(3) = 60 \n" ); document.write( "30(3-1) = 60 Correct \n" ); document.write( "P.S.: this is another answer, in case you need it: they meet when each has traveled 60 miles \n" ); document.write( ": \n" ); document.write( "John \n" ); document.write( " |