document.write( "Question 1068972: Mandy begins bicycling west at 20moh. Liz leaves from the same pint 1 hour later bicycling west at 30mph. When will she catch up with mandy?
\n" ); document.write( "A: define variable
\n" ); document.write( "B: make a chart
\n" ); document.write( "C:set the distance equal to one another (they travel the same diatance) and solve the equation for t.
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Algebra.Com's Answer #684239 by addingup(3677)\"\" \"About 
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When? = time = x
\n" ); document.write( "Mandy: 20x
\n" ); document.write( "Liz: 30(x-1)
\n" ); document.write( "20x = 30(x-1)
\n" ); document.write( "20x = 30x-30 add 30 and subtract 20x on both sides:
\n" ); document.write( "10x = 30
\n" ); document.write( "x = 3 they will meet 3 hours after Mandy left, 2 hours after Liz left
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\n" ); document.write( "Check:
\n" ); document.write( "20(3) = 60
\n" ); document.write( "30(3-1) = 60 Correct
\n" ); document.write( "P.S.: this is another answer, in case you need it: they meet when each has traveled 60 miles
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\n" ); document.write( "John
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