document.write( "Question 1068997:
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document.write( "In order to accumulate enough money for a down payment on a house, a couple deposits $ 567 per month into an account paying 3 % compounded monthly. \r
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document.write( "If payments are made at the end of each period, how much money will be in the account in 6 years?\r
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document.write( "(Round to the nearest dollar.) \n" );
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Algebra.Com's Answer #684237 by addingup(3677)![]() ![]() You can put this solution on YOUR website! Monthly deposits: $567 at the end of each month \n" ); document.write( "Interest earned: 3% compounded 12 times per year \n" ); document.write( "find balance after 6 years \n" ); document.write( "If I got that right, then: \n" ); document.write( "567{[(1+(0.03/12)]^(12*6)-1}/(0.03/12) \n" ); document.write( "= 567(1.197-1)/0.0025 \n" ); document.write( "= 567(78.8) = $44,679.60 \n" ); document.write( "------------------------------------------- \n" ); document.write( "Reference info you should know: \n" ); document.write( "How much money did you put into this account? 567*72 = 40,824 \n" ); document.write( "How much interest did you earn over the 72 months? 44,679.6-40,824 = 3,855.60 \n" ); document.write( ": \n" ); document.write( "John\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |