document.write( "Question 93917This question is from textbook
\n" ); document.write( ": solve the equation. Check your solution.
\n" ); document.write( "1/2y=-3/4y-40
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Algebra.Com's Answer #68422 by checkley75(3666)\"\" \"About 
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1/2Y=-3/4Y-40
\n" ); document.write( "1/2Y+3/4Y=-40
\n" ); document.write( ".5Y+.75Y=-40
\n" ); document.write( "1.25Y=-40
\n" ); document.write( "Y=-40/1.25
\n" ); document.write( "Y=-32 ANSWER.
\n" ); document.write( "PROOF
\n" ); document.write( "1/2*-32=-3/4*-32-40
\n" ); document.write( "-16=24-40
\n" ); document.write( "-16=-16
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