document.write( "Question 1068947: This question is about logs and I don't understand it at all can you please help me solve this equation: Solve the following \"+log%284%29%28x%5E2-6x%29=+2+\".\r
\n" ); document.write( "\n" ); document.write( "So far I have \"+%28x%5E2-6x%29+=+2%2Flog%284%29+\"
\n" ); document.write( " \"+x%5E2-6x-3.321928095++\"\r
\n" ); document.write( "\n" ); document.write( "Now, I'm stuck and I'm not sure if I answered the question or if there is more work to be shown?
\n" ); document.write( "Get back to me as soon as possible, thank you soo much and have a nice day/night!
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Algebra.Com's Answer #684170 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
Let me guess, that you have log(4,(x^2-6x))=2, or as rendered, \"log%284%2C%28x%5E2-6x%29%29=2\". If it is this, then your first step is wrong.\r
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\n" ); document.write( "\n" ); document.write( "Put into exponential form, using base of 4:\r
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\n" ); document.write( "\n" ); document.write( "\"4%5E2=x%5E2-6x\"\r
\n" ); document.write( "\n" ); document.write( "and then\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-6x=16\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-6x-16=0\", and you can try solving this quadratic equation.
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