document.write( "Question 1068891: Peter drops a stick of dynamite down a deep hole near Spruce Mountain. He times it from the moment he lets go and hears the sound exactly 11.20 seconds later. If the speed of sound is 343 meters / second, how deep is this hole? You must take the speed of sound into consideration. Answer in meters. Use g = 9.8 m/sec^2. \n" ); document.write( "
Algebra.Com's Answer #684158 by ankor@dixie-net.com(22740)\"\" \"About 
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Peter drops a stick of dynamite down a deep hole near Spruce Mountain.
\n" ); document.write( " He times it from the moment he lets go and hears the sound exactly 11.20 seconds later.
\n" ); document.write( " If the speed of sound is 343 meters / second, how deep is this hole?
\n" ); document.write( " You must take the speed of sound into consideration.
\n" ); document.write( " Answer in meters. Use g = 9.8 m/sec^2.
\n" ); document.write( ":
\n" ); document.write( "The stick and the sound travel the same distance; dist = speed * time
\n" ); document.write( "let t = stick drop time
\n" ); document.write( "then
\n" ); document.write( "(11.2-t) = sound travel time
\n" ); document.write( ":
\n" ); document.write( "4.9t^2 = 343(11.2-t)
\n" ); document.write( "4.9t^2 = 3841.6 - 343t
\n" ); document.write( "a quadratic equation
\n" ); document.write( "4.9t^2 + 343t - 3841.6
\n" ); document.write( "Using the quadratic formula, I got a positive solution of
\n" ); document.write( "9.82 seconds for the stick to drop
\n" ); document.write( "then
\n" ); document.write( "11.2 - 9.82 = 1.38 seconds for sound to travel back to the surface
\n" ); document.write( ":
\n" ); document.write( "Find the depth of the hole
\n" ); document.write( "343 * 1.38 = 473 meters deep
\n" ); document.write( ":
\n" ); document.write( "Check this by using the falling time of the stick
\n" ); document.write( "4.9(9.82^2) = 473 meter also
\n" ); document.write( ":
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\n" ); document.write( "A student pointed out that my first solution is not correct.
\n" ); document.write( " On thinking it over, I should have used 4.9t^2 for a dropped object, not 9.8 as given.
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