document.write( "Question 1068895: Two​ joggers, one averaging 5
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Algebra.Com's Answer #684139 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "                speed        time          distance\r\n" );
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document.write( "Fast             5           t               d\r\n" );
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document.write( "Slow             4           t+35/60         d\r\n" );
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\n" ); document.write( "\n" ); document.write( "\"35%2F60=5%2A7%2F%285%2A12%29=7%2F12\"\r
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\n" ); document.write( "\n" ); document.write( "-
\n" ); document.write( "\"system%285t=d%2C4%28t%2B7%2F12%29=d%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=d%2F5\"
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\n" ); document.write( "\"4t%2B7%2F3=d\"
\n" ); document.write( "\"4d%2F5%2B7%2F3=d\"\r
\n" ); document.write( "\n" ); document.write( "\"3%2A5%284d%2F5%2B7%2F3%29=3%2A5%2Ad\"\r
\n" ); document.write( "\n" ); document.write( "\"12d%2B35=15d\"\r
\n" ); document.write( "\n" ); document.write( "\"35=3d\"\r
\n" ); document.write( "\n" ); document.write( "\"d=35%2F3\"\r
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