document.write( "Question 93947: differentiate with respect to x : loge3x-3/x \n" ); document.write( "
Algebra.Com's Answer #68413 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
differentiate with respect to x : loge3x-3/x\r
\n" ); document.write( "\n" ); document.write( "First term:
\n" ); document.write( "ln(3x)=ln3+lnx\r
\n" ); document.write( "\n" ); document.write( "d/dx(ln3)+d/dx(lnx)=0+1/x=1/x\r
\n" ); document.write( "\n" ); document.write( "Second term:\r
\n" ); document.write( "\n" ); document.write( "-3/x=-3x^(-1)\r
\n" ); document.write( "\n" ); document.write( "d/dx(-3x^(-1))=3x^(-2)\r
\n" ); document.write( "\n" ); document.write( "So we have:\r
\n" ); document.write( "\n" ); document.write( "1/x+3x^(-2) and we can simplify this:\r
\n" ); document.write( "\n" ); document.write( "1/x+3/x^2 multiply each term by (x^2)/(x^2):\r
\n" ); document.write( "\n" ); document.write( "(x+3)/x^2\r
\n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor
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