document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1068846>Question 1068846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 3,p,q,34 are consecutive terms of an A.P,find the values of p and q </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #684097 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=684097\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The n-th term of an arithmetic progression can be written as:<BR>\n" );
document.write( "a_n = a + (n-1)d, where d is the common difference and a is the 1st term.<BR>\n" );
document.write( "We don't know where the numbers 3 and 34 lie in the sequence, but we know <BR>\n" );
document.write( "that their difference is 3d, since they are 3 places away from each other.<BR>\n" );
document.write( "So we have 3d = 31, or d = 31/3. <BR>\n" );
document.write( "Since consecutive terms differ by d, we have p = 3 + 31/3 = 40/3 and <BR>\n" );
document.write( "q = 40/3 + d = 40/3 + 31/3 = 71/3.<BR>\n" );
document.write( "So the four values in the sequence are 3, 40/3, 71/3, 34<BR>\n" );
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