document.write( "Question 1068754: Find four consecutive integers, where twice the fourth integer equals to 25 less than half the third integer.
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Algebra.Com's Answer #684036 by josgarithmetic(39618) $\"\"$ $\"About$

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n, any integer\r
\n" ); document.write( "\n" ); document.write( "Four consecutive integers: n, n+1, n+2, n+3\r
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\n" ); document.write( "\n" ); document.write( " $\"2%28n%2B3%29=-25%2B%28n%2B2%29%2F2\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"4%28n%2B3%29=-50%2Bn%2B2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4n%2B12=n-48\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3n=-48-12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3n=-60\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28n=-20%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "The consecutive integers are -20, -19, -18, -17. \n" ); document.write( "

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