document.write( "Question 1068781: solve by factoring
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document.write( "a) x^3-2x^2-5x+6=0
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document.write( "b) 3x^3+2X^2-8x+3=0
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document.write( "solve 2x^4-x^3=7x^2-9x+3 \n" );
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Algebra.Com's Answer #684027 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 1/1===-2===-5===6 \n" ); document.write( "=1====-1===-6===0 \n" ); document.write( "(x-1)(x^2-x-6)=0;(x-1)(x-3)(x+2)=0 roots are 1,3,-2 \n" ); document.write( " \n" ); document.write( "=========== \n" ); document.write( "1/3===2===-8===3 \n" ); document.write( "=3===5===-3===0 \n" ); document.write( "(x-1)(3x^2+5x-3)=0; roots are 1,(1/6)(-5+/- sqrt(61)) \n" ); document.write( " \n" ); document.write( "============\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |