document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1068786>Question 1068786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base of a parallelogram is 9 ft more than the height. If the area of the parallelogram is 36 ft squared, what are the measures of the base and the&#8203; height? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #684026 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=684026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The base of a parallelogram is 9 ft more than the height. If the area of the parallelogram is 36 ft squared, what are the measures of the base and the&#8203; height? <BR>\n" );
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document.write( "Area = base*height<BR>\n" );
document.write( "36 = (h+9)h<BR>\n" );
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document.write( "h^2 + 9h - 36 = 0<BR>\n" );
document.write( "h^2+12h-3h-36 = 0<BR>\n" );
document.write( "h(h+12)-3(h+12) = 0<BR>\n" );
document.write( "(h+12)(h-3) = 0<BR>\n" );
document.write( "Positive solution::<BR>\n" );
document.write( "height = 3 ft<BR>\n" );
document.write( "base = 3+9 = 12 ft<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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