document.write( "Question 1068733: Determine the sum to 16 terms of the arithmetic series whose 7th term is 19 and whose 10th term is 25 \n" ); document.write( "
Algebra.Com's Answer #683999 by swincher4391(1107)\"\" \"About 
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Since we are told that we have an arithmetic series, that means there is a common difference between terms. Call it \"d\".\r
\n" ); document.write( "\n" ); document.write( "So, first let's find what that common difference is.\r
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\n" ); document.write( "\n" ); document.write( "We are told that the 7th term is 19\r
\n" ); document.write( "\n" ); document.write( "And that the 10th term is 25.\r
\n" ); document.write( "\n" ); document.write( "So we are adding the common difference to get from the 7th to 8th, 8th to 9th, 9th to 10th. Or a total of 3 times.\r
\n" ); document.write( "\n" ); document.write( "So 19 + 3d = 25\r
\n" ); document.write( "\n" ); document.write( "3d = 6\r
\n" ); document.write( "\n" ); document.write( "So d = 2.\r
\n" ); document.write( "\n" ); document.write( "Now let's find the 1st term. We are told that the 7th term is 19, so we add the common difference 6 times from the 1st term.\r
\n" ); document.write( "\n" ); document.write( "or A_1 + (7-1)*2 = 19\r
\n" ); document.write( "\n" ); document.write( "A_1 + 12 = 19\r
\n" ); document.write( "\n" ); document.write( "A_1 = 7\r
\n" ); document.write( "\n" ); document.write( "So we know the common difference =2, the first term is 7, and we know the number of terms we are adding.\r
\n" ); document.write( "\n" ); document.write( "We still need to know the last term. So the last term can be found by taking a_10 + (6-1)*2 = 25 + 10 = 35
\n" ); document.write( "The sum is:\r
\n" ); document.write( "\n" ); document.write( "number of terms*(1st term + last term)/2\r
\n" ); document.write( "\n" ); document.write( "16*(7+35)/2 = \"highlight%28336%29\"
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